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Step2247 [10]
3 years ago
10

Find the values of x and y using the given​ chord, secant, and tangent lengths.

Mathematics
1 answer:
inn [45]3 years ago
4 0

Answer:

x = 15.65

y = 3.5

Step-by-step explanation:

Step 1

Find the equation for x and y

Equation for x is given as

x² = 7( 7+28) ..........Equation 1

14(14 + y) = x²........ Equation 2

Solving for Equation 1

x² = 7( 7+28)

x² = 7(35)

x² = 245

x = √245

x = 15.65

From Equation 1 , x² has been determined to be 245

Therefore we substitute 245 for y in Equation 2

14(14 + y) = x²........ Equation 2

14(14 + y) = 245

196 + 14y = 245

14y = 245 - 196

14y = 49

y = 49 ÷ 14

y = 3.5

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Let

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Then

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3 years ago
Consider this quadratic equation.
enot [183]

Answer:

1 positive solution (and 1 negative)

the greatest solution is about 2.87

Step-by-step explanation:

so, it is

x² + 2x + 7 = 21

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the general solution to such a quadratic equation is

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in our case

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x = (-2 ± sqrt(2² - 4×1×-14))/(2×1) =

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x2 = -1 - sqrt(15) = -4.872983346...

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2 years ago
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