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3 years ago

Find the values of x and y using the given chord, secant, and tangent lengths.

Mathematics

1 answer:

inn [45]3 years ago

4 0

Answer:

x = 15.65

y = 3.5

Step-by-step explanation:

Step 1

Find the equation for x and y

Equation for x is given as

x² = 7( 7+28) ..........Equation 1

14(14 + y) = x²........ Equation 2

Solving for Equation 1

x² = 7( 7+28)

x² = 7(35)

x² = 245

x = √245

x = 15.65

From Equation 1 , x² has been determined to be 245

Therefore we substitute 245 for y in Equation 2

14(14 + y) = x²........ Equation 2

14(14 + y) = 245

196 + 14y = 245

14y = 245 - 196

14y = 49

y = 49 ÷ 14

y = 3.5

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3 years ago

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3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

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Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

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For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

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Group terms that contain the same variable, and move the constant to the opposite side of the equation

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Complete the square. Remember to balance the equation by adding the same constants to each side

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Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

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therefore

The maximum height is 66 ft

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we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

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For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

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The domain of the function that makes sense is the interval

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Remember that the time can not be a negative number

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If a point is translated right and up, then the image of the point should be to the right and up from the original point, aka the preimage.

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B. Point C could be the image of A.

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C. Point E could be the image of C.

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D. Point D could be the image of A.

D is down and to the right of A so no.

E. Point E could be the image of B.

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F. Point C could be the image of E.

No C is down and to the left of E.

Answers: A C E

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3 years ago

Read 2 more answers

Find the values of x and y using the given​ chord, secant, and tangent lengths.

Find the values of x and y using the given chord, secant, and tangent lengths.