If the standard deviation from the mean for a set of measured values is large it is safe to conclude What

Two fifths of the counties in a bag are mint. There are 34 mint candies. How many candies in total are in the bag?

Helen [10]

Answer: 85 candies

Step-by-step explanation:

34 divide by 2 and then multiply 17 by 5

7 0

3 years ago

Please help me with this question!

Dvinal [7]

Answer:

The two-liter bottle of soda has a unit price of $0.028/ounce.

The case of twelve 12 ounces has a unit price of $0.021/ounce.

The case of twelve 12 ounce can is the better bargain.

Step-by-step explanation:

A two-liter bottle of soda i.e. 67.6 ounces cost $1.89.

So, the unit price (price/ounces) of this type of soda is $\frac{1.89}{67.6} = 0.028$ dollars per ounce.

Again, a case of twelve 12 ounce cans of the same soda costs $2.99.

So, the unit price (price/ounces) of this type of soda is $\frac{2.99}{12 \times 12} = 0.021$ dollars per ounce.

Therefore, the case of twelve 12 ounce can is the better bargain. (Answer)

3 0

3 years ago

Which one of these relationships is different than the other three? <br> A <br> B <br> C<br> D

wlad13 [49]

Answer:

B differs from the others

Step-by-step explanation:

The other lines all have slopes of 5. Graph b has a slope of 5.5

7 0

2 years ago

The scale of scores for an IQ test are approximately normal with mean 100 and standard deviation 15. The organization MENSA, whi

Zina [86]

Answer:

B) 47.5%

Step-by-step explanation:

Refer to the normal distribution chart attached. If 130 is 2 standard deviations higher than the mean (ignore the numbers beneath the percentages), then by the empirical rule, this means that 34%+13.5%=47.5% of adults are between IQs of 100 and 130. Therefore, option B is correct.

5 0

3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.