Answer:
Given that:

where
L(t) represents the length of each day(in minutes) and t represents the number of days.
Substitute the value of L(t) = 750 minutes we get;

Subtract 728 from both sides we get;

Divide both sides by 52 we get;

or

Simplify:

or

Simplify:
days
Therefore, the first day after the spring equinox that the day length is 750 minutes, is 25 days
Answer:
27 m^3
Step-by-step explanation:
9•27+2•31-28= ? Is that what you are asking?
? can be any number except for 3 or -2 as it is already used in (3,4), (-2,-5)