Answer:1.8
Step-by-step explanation:
A 35-inch ribbon was cut into 8 equal lengths.How log was each piece? Describe how the ribbon could be cut into eighths.
1 answer:
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Part A:
The total area = x² + 12x + 20 = (x+2)(x+10)
<span>The width = x+2
∴ Length = area / width = </span>[ <span>(x+2)(x+10) ] / (x+2) = x+10
Part B: </span>
<span>A 2-foot walkway is built around the fountain
</span>
<span>∴ The width = (x+2) + 2 + 2 = x + 6
The length = (x+10) + 2 + 2 = x +14
Part C:
</span><span>the total area covered by the fountain and walkway. </span><span>
= (x+6)(x+14)
= x² + 20 x + 84
See the attache figure for more explanation
</span>
The total area = x² + 12x + 20 = (x+2)(x+10)
<span>The width = x+2
∴ Length = area / width = </span>[ <span>(x+2)(x+10) ] / (x+2) = x+10
Part B: </span>
<span>A 2-foot walkway is built around the fountain
</span>
<span>∴ The width = (x+2) + 2 + 2 = x + 6
The length = (x+10) + 2 + 2 = x +14
Part C:
</span><span>the total area covered by the fountain and walkway. </span><span>
= (x+6)(x+14)
= x² + 20 x + 84
See the attache figure for more explanation
</span>