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frosja888 [35]
3 years ago
10

A store sold 28 pairs of cross-trainer shoes for a total of $2,220. Style A sold for $70 per pair and Style B sold for $90 per p

air. How many of each style were sold?
Mathematics
1 answer:
icang [17]3 years ago
8 0

Answer:

Style A sold 15 pairs while Style B sold 13 pairs

Step-by-step explanation:

Let the number of Style A pairs be A.

Let the number of Style B pairs be B.

The store sold 28 pairs of cross-trainer shoes for a total of $2,220 and Style A sold for $70 per pair while Style B sold for $90 per pair.

This implies 2 things:

A + B = 28 ________________ (1)

and

(70*A) + (90*B) = 2220

=> 70A + 90B = 2220 ________(2)

We now have two simultaneous equations:

A + B = 28 ________________ (1)

70A + 90B = 2220 __________(2)

From (1):

A = 28 - B ________________ (3)

Put (3) in (2):

70(28 - B) + 90B = 2220

1960 - 70B + 90B = 2220

1960 + 20B = 2220

Collecting like terms:

20B = 2220 - 1960

20B = 260

B = 260 / 20

B = 13

Therefore:

A = 28 - 13 = 15

Style A sold 15 pairs while Style B sold 13 pairs.

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Consider U = {x|x is a real number}. A = {x|x ∈ U and x + 2 > 10} B = {x|x ∈ U and 2x > 10} Which statements are true? 5 ∉
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x+2 > 10 solves to x > 8 after we subtract 2 from both sides

So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.


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----------------


Summarizing everything, we can say...

5 is not in set A. True

5 is in set B. False

6 is in set A. False

6 is not in set B. False

8 is not in set A. True

8 is in set B. True

9 is in set A. True

9 is not in set B. False


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