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Bezzdna [24]
3 years ago
13

Systems of equations have one solution.. . Always. . Sometimes. . Never

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0
Systems of equations have one solution SOMETIMES.

There are equations wherein the lines intersect.
There are equations wherein the lines do not intersect so no solutions.
Thus, the answer is sometimes.
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B. 2(3x - 5) = 2x + 6
Leto [7]

Answer:

x = 4

Step-by-step explanation:

Given

2(3x - 5) = 2x + 6 ( divide both sides by 2 )

3x - 5 = x + 3 ( subtract x from both sides )

2x - 5 = 3 ( add 5 to both sides )

2x = 8 ( divide both sides by 2 )

x = 4

8 0
3 years ago
Read 2 more answers
If 5^2x = 1, what is the value of 'x' ?​
SVETLANKA909090 [29]

Answer:

x = 0

Step-by-step explanation:

5^0 is 1, meaning that x must equal to 0 for the answer to be 5^0.

6 0
2 years ago
Read 2 more answers
The ancient Greeks could bisect an angle using only a compass and straightedge.A. TrueB. False
Gala2k [10]

Answer: True.

The ancient Greeks could bisect an angle using only a compass and straightedge.

Step-by-step explanation:

The ancient Greek mathematician <em>Euclid</em> who is known as inventor of geometry.

The Greeks could not do arithmetic. They had only whole numbers. They do not have zero and negative numbers.

Thus, Euclid and the another Greeks had the problem of finding the position of an angle bisector.

This lead to the constructions using compass and straightedge. Therefore, the straightedge has no markings. It is definitely not a graduated-rule.

As a substitute for using arithmetic, Euclid and the Greeks learnt to solve the problems graphically by drawing shapes .

5 0
3 years ago
Read 2 more answers
Find the area of the composite figure.
larisa86 [58]
Find the area of all the separate figures and add them together
area of rectangle = length x width
11 x 3 = 33 ft
area of square = a^2
3^2 = 9ft
area of triangle = base x height over 2
11 x 3 = 33
33 over 2 = 16.5 ft
33 + 9 + 16.5 = 58.5 ft ^ 2
8 0
3 years ago
Kevin is observing the population of the fish he put into a pond. He built a pond and populated it with 500 fish. The population
laila [671]

Here we will use exponential form, which is

y = y_{0} e^{kt}

Initial value, y0 = 500

Double of 500 = 1000

1000 = 500e^{k*1}

2 = e^k

k= ln (2)

Required equation is

y=500e^{x ln2} \\ y= 500 (2)^x

6 0
3 years ago
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