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allochka39001 [22]
3 years ago
5

A test statistic is found to have a P-value of .015. Which of the following statements are true?

Mathematics
1 answer:
Luda [366]3 years ago
8 0

Answer:

Option a) I and III only

Step-by-step explanation:

given that a test statistic is found to have a P-value of .015.

In hypothesis testing after finding out test statistic as difference between hypothesises mean and sample mean divided by standard error of sample we find out p value.

Significance level, known as alpha is fixed as 5% or 1% or 10% depending on the matter of interest

If p value calculated is less than our significance level i.e. alpha we reject null hypothesis

Here p = 0.015 is less than 5% and 10% but greater than 1%

So we reject at 5% and 10% level and but accept at 1% level

Correct options would be:

I. This finding is significant at the .05 level of significance.

III. The probability of getting a test statistic as extreme (or more extreme) as this one by chance alone is .015

Option a) I and III only

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Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

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3 years ago
Answer please and explain
Fiesta28 [93]

Answer:

C=84

Step-by-step explanation:

Since you use 3 for pi. You plug the radius into the formula. C=2×3x14=84

5 0
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deff fn [24]

Answer:

thxs :)

Step-by-step explanation:

4 0
3 years ago
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