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4 years ago

Perpendicular Lines please help me guys I'm lostt

Mathematics

1 answer:

mamaluj [8]4 years ago

4 0

9 = 2(6) - b
9 = 12 - b
-3 = b

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Given O PQRS, solve for x.

bonufazy [111]

Answer: A) 2

Step-by-step explanation: I just got it good

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3 years ago

PLZ ANSWER ASAP!!! WILL GIVE BRAINLIEST!!!

larisa86 [58]

Answer:

Face

Step-by-step explanation:

Face is the correct answer.

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4 years ago

Solve the equation<br>-84= 6(p-8)

MrRa [10]

Answer:

-6

Step-by-step explanation:

-84=6(p-8)

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3 years ago

Read 2 more answers

-6 + 2x = 14 this is my question pls answer looool

ArbitrLikvidat [17]

Answer:

$x = 10$

Step-by-step explanation:

$- 6 + 2x = 14 \\ 2x = 14 + 6 \\ 2x = 20 \\ x = 10$

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3 years ago

Read 2 more answers

The first term in a geometric sequence is 54, and the 5th term is 2 / 3. Find an explicit form for the geometric sequence.

quester [9]

Answer: $ar^{n-1}=54(\dfrac{1}{3})^{n-1}$

Step-by-step explanation:

The nth term for a geometric sequence is given by :-

$a_n=ar^{n-1}$ (1)

We are given that The first term in a geometric sequence is 54. i.e. a=54

5th term= $\dfrac{2}{3}$ (2)

Put n=5 and a= 54 in (1), we get

$a_5=(54)r^{4}=$ (3)

From (2) and (3), we have

$\Rightarrow(54)r^{4}=\dfrac{2}{3}\\\\\Rightarrow r^4=\dfrac{2}{3}\times\dfrac{1}{54}=\dfrac{1}{3\times27}=\dfrac{1}{81}\\\\\Rightarrow\ r=(\dfrac{1}{81})^{\frac{1}{4}}=\dfrac{1}{3}$

Explicit form for the geometric sequence: $ar^{n-1}=54(\dfrac{1}{3})^{n-1}$

3 0

4 years ago