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3 years ago

If $560 is sheared in the ratio 2:3:9 , the difference between the largest and the smallest shares is

Mathematics

1 answer:

Lesechka [4]3 years ago

7 0

Answer:

The difference between the largest and the smallest shares is $280

Step-by-step explanation:

Total amount to be shared = $560

Ratios of share are 2:3:9 => Total of 14 equal portions

To get one portion, $560 / 14 = $40

First share is 2, therefore $40 x 2 = $80 (smallest share)

Second share is 3, therefore $40 x 3 = $120

Third share is 9, therefore $40 x 9 = $360 (largest share)

<u>TOTAL = $560</u>

The difference between the largest and the smallest = $360 - $80

= $280

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Tell whether the ordered pair is a solution to the equation.<br><br><br> (1, 3); 4x – 3y = -5

Bumek [7]

Answer:

Yes

Step-by-step explanation:

4(1)-3(3)=-5

4-9=-5

-5=-5

8 0

2 years ago

The town of worman grove has collected 28,481 pens for school supplies drive. Their goal is 30,000 pens .Show how to use countin

frosja888 [35]

Answer:

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Step-by-step explanation:

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3 years ago

What is the value of x in the equation below 6 (x - 8) equals 72

olga_2 [115]

Here is the equation:

$6(x-8)=72$

In the equation, 6 is being multiplied by x - 8. There are two ways to solve this equation.

FIRST METHOD

You need to remove the parentheses by multiplying everything in the parentheses by 6.

$6(x-8) = (6\times x) + (6 \times -8)$

Multiply:

$6 \times x = 6x\\6 \times -8 = -48$

Remember:

NEGATIVES

Negative(-) times(×) negative(-) = positive(+)

Negative(-) times(×) positive(+) = negative(-)

Negative(-) divided(÷) by positive(+) = negative(-)

Negative(-) divided(÷) by negative(-) = positive(+)

POSITIVES

Positive(+) times(×) positive(+) = positive(+)

Positive(-) times(×) negative(-) = negative(-)

Positive(+) divided(÷) by positive(+) = positive(+)

Positive(+) divided(÷) by negative(-) = negative(-)

Now combine the two values and rewrite the equation:

$6x+-48 \rightarrow 6x-48=72$

Since you're looking for x alone, you will need to remove the -48. This can be done by adding 48 to both sides, -48+48=0, which cancels it out).

$6x-48+48=72+48\\6x=120$

Lastly, divide both sides by 6 to leave x alone.

$\frac{6x}{6} = \frac{120}{6}$

$x=20$

SECOND METHOD

While the first step is somewhat complicated, there is a much easier way.

$6(x-8)=72$

Start by dividing both sides by 6 to remove the number next to the parentheses.

$\frac{6(x-8)}{6} =\frac{72}{6}$

$x-8=12$

(The 6 is cancelled out since 6 divided by 6 equals 1, and 1 × any number is that number).

Now you need to leave the variable alone, which can be done by adding 8 to both sides(-8+8=0 and -8 is cancelled out).

$x-8+8=12+8\\$

$x=20$

Either method can be used, but the second one is definitely shorter!

The answer is x = 20.

8 0

3 years ago

Read 2 more answers

"Hang time" is the time you are suspended in the air during a jump. Your hang time t in seconds is

Artyom0805 [142]

Answer:

2.5/5V

Step-by-step explanation:

Given the expression for hang time t = 5Vh

A kite sailor has a hang time of 2.5 secs

Height of the kite’s sailor’s jump = ?

Therefore 2.5 = 5Vh

Divide both sides by 5V

2.5/5V = h

h = 2.5/5V

4 0

3 years ago

Hi!

Elina [12.6K]

Answer:

404.09x cm³ (to 5 s.f.),

where x is the unknown height of the shape.

Step-by-step explanation:

Volume of the shape

= base area × height

= (large semicircle- small semicircle) × thickness of shape

Area of circle= $\pi {r}^{2}$

Area of semicircle= $\frac{1}{2} (\pi)( {r}^{2} )$

Diameter of small circle= 14

Radius= diameter ÷2

radius= 14 ÷2

radius = 7 cm

Area of small semicircle

$= \frac{1}{2} (\pi)( {7}^{2} ) \\ = \frac{49}{2} \pi$

Radius of large semicircle

= 35 ÷2

= 17.5 cm

Area of large semicircle

$= \frac{1}{2} (\pi)( {17.5}^{2} ) \\ = \frac{1225}{8} \pi$

Base area of shape

$= \frac{1225}{8}\pi - \frac{49}{2} \pi \\ = \frac{1029}{8} \pi$

Since the height if the shape is not given, I'm afraid I cant help you find the volume.

Let the height of the shape be x cm.

Volume of shape= $\frac{1029x}{8} \pi \: cm^{3}$

3 0

3 years ago