
Both equations are equivalent, so there are infinitely many solutions.
First multiply all terms by z
8-z^2=4z
Then order into standard form
-z^2-4z+8=0
Multiply the equation by -1
z^2+4z-8=0
Plug into quadratic equation
-4±√16-4(-8)
-4±√48
(-4±4√3)/2
-2±2√3
Final answer: z=-2± 2√3
The answer is 42.3
Step by Step:
Let our variable be n, standing for number.
3.6(x) + 4.5(y) = n
3.6(3) + 4.5(7) = n
10.8 + 31.5 = n
n = 42.3
Answer:
Step-by-step explanation:
a) -14 , -9 , -4 , 1 ................
Common difference = d = 2nd term - 1st term
= -9-[-14]
= -9 + 14
d = 5
The next term can be got by adding 5 to the previous term
5th term = 1 + 5 = 6
6th term = 6 + 5 = 11
7th term = 11 + 5 = 16
Next 3 terms are : 6 , 11 , 16

The most common scenario was the low-fuel landing. It was there in 25 % of the tests. The number of tests was 25+115=140 tests (adding up the failed and passed test.
So to find our how many were trained in the most common scenario, we have to calculate25% of 140.
25/100*140=(i calculate frist 25/100. I divide both by 25, we have 1/4)1/4*140 = In order to calculate this, we need to divide 140/4. This is:
35____140:4 12 20 20 ==
so the correct answer is 35.