The height of the snow was 84 inches in the beginning of the week. it melts at a rate of 0.15 inches per hour. how many hours wo
1 answer:
Answer:
146.66 hours.
Step-by-step explanation:
Given: Height of snow at the beginning is 84 inches.
Snow melting rate is 0.15 inches per hour.
Now, finding number of hours to reach 62 inches of snow.
First lets find the number of inches reduced.
Reduced inches of snow=
∴ Reduced inches of snow is 22 inches after melting at 0.15 inches per hour.
Next finding hours to melt 22 inches of snow.
Time=
⇒ Time=
Hence, 146.66 hours would it take for the snow to reach 62 inches.
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Answer:
<h3><em>D. 880 = 45d + 70; 18 days.</em></h3>Step-by-step explanation:
We are given fixed monthly charge = $70.
The cost of preschool per day = $45.
Number of days = d.
Total cost of d days = cost per day × number of days + fixed monthly charge.
Therefore, we get equation
880 = 45×d+70
<h3>880 = 45d +70.</h3>Now, we need to solve the equation for d.
Subtracting 70 from both sides, we get
880-70 = 45d +70-70
810=45d
Dividing both sides by 45, we get
18=d.
Therefore,<em> 18 days Barry attended preschool last month.</em>
<em>Therefore, correct option is D option.</em>
<h3><em>D. 880 = 45d + 70; 18 days.</em></h3>Answer:
i think this is what u are,asking
Answer:
The probability is 0.971032
Step-by-step explanation:
The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.
The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:
In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:
(eq. 1)
So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:
P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)
We can also calculated that as:
P(x ≥ 5) = 1 - P(x ≤ 4)
Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)
Then, if we calculate every probability using eq. 1, we get:
P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765
P(x ≤ 4) = 0.028968
Finally, P(x ≥ 5) is:
P(x ≥ 5) = 1 - 0.028968
P(x ≥ 5) = 0.971032