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Alex787 [66]
3 years ago
15

Which congruence postulate or theorem shows that the triangles below are congruent?

Mathematics
1 answer:
saul85 [17]3 years ago
5 0

Answer:

A. AAS

Step-by-step explanation:

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a stack of quarters is 5 mm. how many quarters are in a stack that is 5 cm tall? show the steps you took and explain your answer
Naddik [55]
Well, scence you don't know how many quarters are in a stack of 5mm, ill give a variable answer...there's 10x as many quarters in the stack of cm than the stack of millimeters, because 5mm=1/2 cm, and 5/.5=10
8 0
3 years ago
Given that two tangent lines are constructed from the shared point A outside a circle to the points of tangency B and C, what is
Talja [164]
The answer would be C! Like the person stated above ''tangents to the same circle from the same point measure the same''.
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3 years ago
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Siobhan needs a $7,000 personal loan. Which loan option would require her to pay back the least amount of money?
Ivahew [28]

Answer:

18 month loan with a 13% annual simple interest rate

Step-by-step explanation:

4 0
2 years ago
23.
Crazy boy [7]

Answer:

The number that cannot be the largest possible 6-digit number is;

(D) AAABCB

Step-by-step explanation:

From the question, we have;

A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

When C > A > B

The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;

AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB

∴ AAABBC > AAABCB and <u>AAABCB</u>, cannot be the largest possible 6-digit number

3 0
2 years ago
Can someone complete the square
pshichka [43]
To do these, start by looking at the "b" value -6.
divide it by 2

-6/2 = -3

now square this number

(-3)^2 = 9

this is what you need for the "c" value

there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)

y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4

vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.


7 0
3 years ago
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