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2 years ago

A bracelet is made by stringing together four beads. Each bead is either red or green. How many different color patterns are

Mathematics

2 answers:

JulijaS [17]2 years ago

7 0

Answer:

3 or 5, depends on the bracelet can be fully green or red. If you have to have both colours then it's 3.

Step-by-step explanation:

RRRG

RRGG

RGGG

GGGG?

RRRR?

mezya [45]2 years ago

4 0

Answer:

Step-by-step explanation:

RRRR

RRRG

RRGG

RGRG

RGGG

GGGG

6, (You problary forgot hat 2 green and 2 red have 2 possilbilties, RRGG and RGRG)

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scZoUnD [109]

Answer:

x = 5

Step-by-step explanation:

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<A = <C = 73

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<B = 180 - 146

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6x + 4 = 34

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3 years ago

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
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The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

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<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

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$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

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vazorg [7]

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yes htey are good

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elena-s [515]

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3 years ago

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Nonamiya [84]

Answer:

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