So i'm assuming your eqtn is h = -16t^2 + 27t + 10
and we're looking for t = ? when h = 0
=> 16t^2 - 27t - 10 = 0
(16t + 5)(t - 2) = 0
t = 2 and t = -5/16
answer 2 seconds
Answer:
-Exponential Decay
-Decay factor is (1-0.05)
Step-by-step explanation:
-Given that the number decreases by a defined rate each year from the initial size by 5%,
-This is an exponential decay function of the form:

Where:
is the quantity/size after time t
is the initial size
is the rate of decay
-Our function can the be written as

Hence, the decay rate/factor is 0.05
#Alternatively
The exponential decay can be of the form:

Where:
y is the size at time x, a is the initial size, x is time and b is the decay factor.
b is of the form 

Hence, the decay factor is (1-0.05)
Answer:
the answer is -33 srry couldn't explain :(
the answers are B,D and F
F(x) = x² + x - 20 = x² + 5x - 4x - 20 = x(x + 5) - 4(x + 5) = (x + 5)(x - 4)
f(x) = 0 ⇔ (x + 5)(x - 4) = 0 ⇔ x + 5 = 0 or x - 4 = 0 ⇒ x = -5 or x = 4
Answer: C. x = -5 and x = 4.