The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
Sec y = q/r
Step-by-step explanation:
Sin y = 7/q
tan y = 7/r
Mathematically cos y = sin y/tan y
But sec y = 1/cos y
So therefore sec y = tan y/sin y
So that would be ;
7/r divided by 7/q
= 7/r * q/7
= q/r
Answer:
dzfvxcafs za
Step-by-step explanation:
qwertyuio79151
Answer:
B. Multiply by 5 on both sides of the equation. C. 7 × 5 = 35. E. Dolev had 35 pretzels.
Step-by-step explanation:
B. get p by itself
C. if each received 7 and there was 5 people, 5 times 7 would be the total of pretzels
E. 5 times 7 equals 35.
13.45 will be the answer
since we are finding the hypotenuse, the formula is a^2 + b^2 = c^2
this will then be 10^2 + 9^2 = c^2
181=c^2
c=13.45 :)