Question

the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh a total of 249 ounces.

Answer 1

Keywords:

System of equations, variables, hardcover version, paperback version, books

For this case we must construct a system of two equations with two variables. Let "h" be the number of hardcover version books, and let "p" be the number of paperback version books. If the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces, to reach a total of 249 ounces we have:

$7h + 5p = 249$ (1)

On the other hand, if there are Forty-five copies of the book then:

$h + p = 45$ (2)

If from (2) we clear the number of books paperback version we have:

$p = 45-h$

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply$5 * p = 5 (45-h)$

So, $x = 5 (45-h)$

Answer:

$x = 5 (45-h)$

Option D

Answer 2

Answer:

The value of x = 5(45-h)

Step-by-step explanation:

Lets the hardcover books be represented by = h

Let the paperback books be represented by = p

Given is that the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces and 45 copies of the boo weigh 249 ounces, so equations are :

7h + 5p = 249    .....(1)

h + p = 45  or p = 45 - h ..... (2)

Now in the table the total weight of the paperback version books is given by 'x' and each paperback version book weighs 5 ounces so we will multiply 5 on both sides giving:

5 * p = 5(45-h)  ;

This further gives x = 5(45-h)