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Sphinxa [80]
3 years ago
10

What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0
Implicit differentiation
take the deritivive with respect to x

first
y+2=(1/2)(x^2)-2sin(y)
take deritivitive
dy/dx+0=1/2(2x)-2(cosy)dy/dx
dy/dx=x-2cosy(dy/dx)
add 2cosy(dy/dx) to both sides
dy/dx+2cosy(dy/dx) =x
undistribute dy/dx
dy/dx(1+2cos(y))=x
divide both sides by 1+2cos(y)
\frac{dy}{dx}= \frac{x}{1+2cos(y)}
at (2,0)
x=2
y=0

\frac{dy}{dx}= \frac{2}{1+2cos(0)}
\frac{dy}{dx}= \frac{2}{1+2(1)}
\frac{dy}{dx}= \frac{2}{1+2}
\frac{dy}{dx}= \frac{2}{3}
the slope is 2/3
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