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Akimi4 [234]
2 years ago
9

a bank loaned out $18,000, part of it at the of 8% per year and the rest at 16% per year. if the interest received in one year t

otaled $2000, how much was loaned at 8%?
Mathematics
1 answer:
labwork [276]2 years ago
7 0
1,800 bc you take away the 8%
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Use function notation to write the equation of the line
blondinia [14]

f(x)=mx+b\to y=mx+b

We have two points:

(-3,\ 0);\ (-4,\ 7)

The point slope form of the line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute

m=\dfrac{7-0}{-4-(-3)}=\dfrac{7}{-1}=-7

y-0=-7(x-(-3))\\\\y=-7(x+3)\\\\y=-7x-21

Answer:

f(x)=-7x-21

8 0
3 years ago
I only have 8 minutes left please help!!! The expression h(x)= -5x2 + 25x + 70 can be used to estimate the height(h), in meters,
rewona [7]
Hence x is 7 seconds

8 0
2 years ago
Mark ran 875 miles this year in the track club.Mark ran in 52 track meets and ran the same number of miles in each.How many mile
shepuryov [24]

Answer:

The number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

Step-by-step explanation:

Let us assume that the number of miles Mark run in each track meet be x.

As given

Mark ran 875 miles this year in the track club.

Mark ran in 52 track meets and ran the same number of miles in each.

Than the equation becomes

52 × x = 875

x = \frac{875}{52}

x = 16 \frac{43}{52}\ miles

Therefore the number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

7 0
3 years ago
write the point slope form of an equation of the line that passes through (-2 5) and has an undefined
Nana76 [90]

Answer:

  no solution

Step-by-step explanation:

Any of the "-slope" or "slope-" formulas for a line cannot be used when the slope is undefined.

The equation of the desired line is x = -2. It cannot be put into the form y = ....

3 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

4 0
3 years ago
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