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lina2011 [118]
3 years ago
11

Solve for x. −3x + 2b > 8

Mathematics
2 answers:
RoseWind [281]3 years ago
6 0
I think the answer is
x < (2b -8) / 3
or
x < 2b/3 - 8/3
Brums [2.3K]3 years ago
6 0
If you don't know what b= then x < \frac{-8+2b }{3}
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What is the equation for the vertical asymptote of the function shown below? f(x)=3x^4-3/2x-5
levacccp [35]
f(x)= \frac{3x^4}{2x-5}

the va's are where x is undefined, or where the denomenator is zero
first simplify if applicable
cannot simplify

set denom to zero
2x-5=0
2x=5
x=2.5

the vertical assemtote is vertical so it is x=2.5 or 5/2

the VA is x=5/2
3 0
2 years ago
PLEASE HELP I NEED A GOOD GRADE ON THIS
VladimirAG [237]

Answer:

B = 1/243

Step-by-step explanation:

6 0
3 years ago
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A number n is multiplied with —9 to give 63. Find the value of n.
FrozenT [24]

Answer:

n = -7

Step-by-step explanation:

63÷-9

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2 years ago
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The height of a ball thrown vertically upward from a rooftop is modelled by h(t)= -4.8t^2 + 19.9t +55.3 where h (t) is the balls
nikitadnepr [17]

By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.

<h3>How to determine the maximum height of the ball</h3>

Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:

- 4.8 · t² + 19.9 · t + (55.3 - h) = 0

The height of the ball is a maximum when the discriminant is equal to zero:

19.9² - 4 · (- 4.8) · (55.3 - h) = 0

396.01 + 19.2 · (55.3 - h) = 0

19.2 · (55.3 - h) = -396.01

55.3 - h = -20.626

h = 55.3 + 20.626

h = 75.926 m

By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.

To learn more on quadratic equations: brainly.com/question/17177510

#SPJ1

6 0
1 year ago
A tree that is 14 feet tall casts a shadow that is 30 feet long. Find the angle of the elevation from the top of the shadow to t
Umnica [9.8K]

Let x = angle we must find

tan x = 14/30

arctan(tan x) = arctan(14/30)

x = 25.0168934781

Answer: 25 degrees

8 0
3 years ago
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