Answer:
$1672.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Average speed = distance/time
Trip to dry dock
Let x be the velocity
Time = 2hours
Distance = average speed ×time
Distance = x×2
Distance = 2x
Return trip
Velocity = x-5 (5 miles per hour faster on the trip there than on the return trip)
Time = 3hrs
Distance = 3(x-5)
Since the distance is the same both to and fro;
2x = 3(x-5)
2x = 3x -15
2x-3x = -15
-x = 15
x = 15
Hence the aircraft carrier's average speed on the outbound trip is 15miles/hour
Circumference = diameter * PI
diameter = circumference / PI
diameter = 60 / 3.14159
diameter =
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<span>
<span>
19.0986</span></span></span>
96 = 192 * (1/2) ;
48 = 96 *(1/ 2) ;
24 = 48 *(1/2) ;
. . . . . . . . . .
It'a a geometric sequence with common ratio, r = 1 / 2 .
The correct answer is the third one (x,y) - (-x, -y)