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saw5 [17]
2 years ago
6

Use the long division method to find the result when 82% + 28x2 + 14x – 13 is

Mathematics
1 answer:
MaRussiya [10]2 years ago
7 0

Answer:

Step-by-step explanation:

Free brainliest to the first who answers and 100 points!!!!! also a thanks and a five star

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Describe the distribution of the data and if the mean or median would be a better measure of center for each. Include outliers.
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Is there a picture you can take

Step-by-step explanation:

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3 years ago
In the metric system, which of the following is correct? a:) 1,000= 1 milliliter
Maksim231197 [3]
The correct answer for the given question above would be option C. In the metric system, the one that has shown a correct equivalent of measurement is 100 centimeter = 1 meter. And in every 1 centimeter, there is 0.01 meter. The rest of the options are not correct so the answer is C. 
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3 years ago
The volume of this math problem<br>​
Brrunno [24]
Your answer will be “1200”
5 0
3 years ago
Read 2 more answers
What is the perimeter of this figure? fractions
Alona [7]

Answer:

A

Step-by-step explanation:

You can add the numbers to get the perimeter

10 1/3 + 15 2/3 = 26

18 1/4 + 24 1/4= 42 1/2

26 + 42 1/2= 68 1/2

That is answer choice A

7 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
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