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3 years ago

NEED HELP FAST PLEEEEEAAASSSEEEE 0o0

Mathematics

2 answers:

sukhopar [10]3 years ago

7 0

Answer:

there is no x to solve, so there is no answer to that.

UNO [17]3 years ago

5 0

Answer:

False

it doesn’t equal that

Step-by-step explanation:

You might be interested in

If you transform x 2 + y 2 = 25 into 4x 2 + 4y 2 = 25, which option below describes the effect of this transformation on the rad

FromTheMoon [43]

Answer

c. It divides the radius by 2.

Explanation

The general equation of a circle is

(x-h)² + (y-k)² = r²

Where (h, k) makes the coordinates of the circle and r the radius.

x² + y² = 25 For this equation,

center (0, 0)

Radius = √25 = 5

4x² + 4y² = 25 First simplify this equation

4x² + 4y² = 25 ⇒ x² + y² = 25/4

center (0, 0)

Radius = √(25/4) = 5/2

The radius has been divided by 2

5 0

3 years ago

Read 2 more answers

STION 1

Lorico [155]

Answer:

1.1.1- Michael has 200 lovebirds in total

1.1.2- There are 40 birds in each cage

1.1.3- 120/80 = 3/2

Step-by-step explanation:

120+80=200

200÷5=40

120÷40=3, 80÷40=2

7 0

3 years ago

Does the graph represent a function?

Musya8 [376]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Select the two values of x that are roots of this equation. 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

$\frac{5(+-)\sqrt{25-8}}{4}$

$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

$\frac{5(+-)\sqrt{17}}{4}$

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

8 0

3 years ago

HELP HELP HELP HELP HELP HELP PLEASE I BEG U

kari74 [83]

Answer:

-3.2

Step-by-step explanation:

Do you have to work this out on paper because I just used a calculator but just add 3.1 + -6.3.

5 0

3 years ago