Answer:
She will be 17
Step-by-step explanation:
My sister is like that but she's graduating in 22'
Answer:
not
Step-by-step explanation:
![\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%3D)
First is A and Second is B
Let's find A*B
![\left[\begin{array}{ccc}-2(-2)+4*3&-2*1+4*7\\1(-2)+3*3&1*1+3*7\end{array}\right] =\left[\begin{array}{ccc}16&26\\7&22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B4%2A3%26-2%2A1%2B4%2A7%5C%5C1%28-2%29%2B3%2A3%261%2A1%2B3%2A7%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2626%5C%5C7%2622%5Cend%7Barray%7D%5Cright%5D)
b)
![\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right] \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%3D)
Now let's find B*A
![\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B1%2A1%26-2%2A4%2B1%2A3%5C%5C3%28-2%29%2B7%2A1%263%2A4%2B7%2A3%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-5%5C%5C1%2623%5Cend%7Barray%7D%5Cright%5D)
c) They are not
Step-by-step explanation:
f加班7u后7个6 个预告v78 yi不同承认TVB员工
yesenia has 9 blocks. misty has 15.
15 + 9 = 22.
for the values of the blocks, yesenia has 17 and misty has 68.
17 + 68 = 85.
hope i helped!
9514 1404 393
Answer:
x = 16
Step-by-step explanation:
Either or both of the right triangles can be used to find x. Or, triangle ABC could be used. All numbers are assumed to be degrees.
<u>Using ∆ABD</u>
55 +90 +2x+3 = 180
2x = 32 . . . . . . subtract 148
x = 16
<u>Using ∆BCD</u>
50 +90 +2x+8 = 180
2x = 32 . . . . . . subtract 148
x = 16
<u>Using ∆ABC</u>
55 +(2x +3) +50 +(2x +8) = 180
4x = 64 . . . . . . . subtract 116
x = 16
