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nekit [7.7K]
4 years ago
15

Solve |y + 2| > 6 im so confused

Mathematics
1 answer:
Talja [164]4 years ago
3 0

Answer:

Below

Step-by-step explanation:

● |y+2| > 6

● y+2 > 6 or y+2 < -6

Add -2 in both sides in the two inequality.

● y+2-2 > 6-2 or y+2-2 < -6-2

● y > 4 or y< -8

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What method would you use to square the value 3 + √-1 ? In what other cases would you use this method? Explain.
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Answer:

1) the types of number are the negative integers (e.g √-1 √-3 √-5 are not defined)

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3) the answer is No, proof:  √-1 - 3 is not defined because √-1 doesn't exist

4) the answer is Yes, proof: (√-1 )²=  -1 this is a real number

5) the answer is No, proof:  (√-1 )^3=  (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist

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7) the result would not be defined with the following cases:

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 i²= -1, it implies i= √-1

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9) it is used for finding complex roots of a number

Step-by-step explanation:

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