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3 years ago

The electron ____ of an element shows the arrangement of electrons within an atom

Chemistry

1 answer:

Verdich [7]3 years ago

7 0

The electron ring dors

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At a certain temperature the rate of this reaction is first order in HI with a rate constant of 0.0632 s

kirza4 [7]

Answer:

$28.037\ \text{s}$

Explanation:

$[A]_0$ = Initial concentration = 1.28 M

$[A]$ = Final concentration = $0.17[A]_0$

k = Rate constant = 0.0632 s

t = Time taken

For first order reaction we have the relation

$kt=\ln\dfrac{[A]_0}{[A]}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{[A]}}{k}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{0.17[A]_0}}{0.0632}\\\Rightarrow t=28.037\ \text{s}$

Time taken to reach the required concentration would be $28.037\ \text{s}$ .

8 0

3 years ago

How many grams is 5.4x10 to the 23 molecules of al2o3?

8090 [49]

Answer:

91.49 grams

Explanation:

No of molecules = no of moles × Avogadro's number

No of moles = No of molecules / Avogadro's number

Number of moles = 5.4×10^23/6.02×10^23

Number of moles = 0.897 moles of Al2O3

Number of moles = mass in gram / molar mass

Mass in gram = number of moles× molar mass

Mass in gram = 0.897× 102

91.49 grams

5 0

3 years ago

On the periodic table, which group contains the noble gases? the last group A.the second group B.the fourth group C.the fir

Leni [432]

There you go your welcome

4 0

4 years ago

What are isotopes......

LiRa [457]

I answered that in your last question refer to your answer in section 2

8 0

4 years ago

Read 2 more answers

In a particular experiment at 300 ∘C, [NO2] drops from 0.0100 to 0.00800 M in 100 s. The rate of appearance of O2 for this perio

Tems11 [23]

Answer:

$1\times{10}^{-5}\frac{M}{s}$

Explanation:

The stoichiometry for this reaction is

$2NO_2\rightarrow2NO+O_2$

The rate for this reaction can be written as

$-r_{NO_2}=-\frac{d\left[NO_2\right]}{dt}=\frac{(0.01-0.008)M}{100s}=2\times{10}^{-5}\frac{M}{s}$

This rate of disappearence of $NO_2$ can be realated to the rate of appearence of $O_2$ as follows (the coefficients of each compound are defined by the stoichiometry of the reaction)

$-r_{O_2}=-r_{NO_2}\times\frac{coefficient\ O_2\ }{coefficient\ NO_2}=2\times{10}^{-5}\frac{M}{s}\times\frac{1\ mole\ O_2\ }{2\ mole\ NO_2}=1\times{10}^{-5}\frac{M}{s}$

6 0

4 years ago