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allochka39001 [22]
2 years ago
7

What would the products of a double-replacement reaction between KBr and CaO be? (Remember: In double-replacement reactions, the

two cations switch places and the two anions switch places.) O A. CaBr and KO OB. KBr and CaO C. CaBr₂ and K₂0 O D. Br₂0 and Cak₂​
Chemistry
1 answer:
professor190 [17]2 years ago
6 0

The products formed are potassium nitrate and silver bromide (AgBr).

Double replacement or double displacement reactions are the reactions in which the positive ions and negative ions of the two reactants interchange to form the products. These reactions are carried out based on their position in the reactivity series.

The elements lying above in the reactivity series will be able to displace the elements that lie below in the reactivity series.

For the reaction of potassium bromide and silver nitrate, the reaction follows:

KBr(aq) + AgNO_{3} (aq) -- > AgBr(s) + KNO_3(aq)

The resulting products are potassium nitrate and silver bromide ( AgBr ).

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The solubility of acetanilide in hot water (5.5 g/100 ml at 100∘C) is not very great, and its solubility in cold water (0.53 g/
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Answer:

89.4%

Explanation:

Initially, there is 5.0 of the acetanilide in 100 mL of water, then the solution is chilled at 0ºC. The solubility represents the amount that the solvent (water) can dissolve of the solute (acetanilide). So, at 0ºC, 100 mL of water can dissolve till 0.53 g of the compound, the rest will precipitate and will be recovered.

So, the mass that is recovered is 5.0 - 0.53 = 4.47 g

The percent recovery is:

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