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allochka39001 [22]
2 years ago
7

What would the products of a double-replacement reaction between KBr and CaO be? (Remember: In double-replacement reactions, the

two cations switch places and the two anions switch places.) O A. CaBr and KO OB. KBr and CaO C. CaBr₂ and K₂0 O D. Br₂0 and Cak₂​
Chemistry
1 answer:
professor190 [17]2 years ago
6 0

The products formed are potassium nitrate and silver bromide (AgBr).

Double replacement or double displacement reactions are the reactions in which the positive ions and negative ions of the two reactants interchange to form the products. These reactions are carried out based on their position in the reactivity series.

The elements lying above in the reactivity series will be able to displace the elements that lie below in the reactivity series.

For the reaction of potassium bromide and silver nitrate, the reaction follows:

KBr(aq) + AgNO_{3} (aq) -- > AgBr(s) + KNO_3(aq)

The resulting products are potassium nitrate and silver bromide ( AgBr ).

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Which of the following is a molecular formula for a compound with an empirical formula of CH2O and a molar mass of 150. g/mol.
trapecia [35]

Answer:

C₅H₁₀O₅

Explanation:

Let's consider a compound with the empirical formula CH₂O. In order to determine the molecular formula, we have to calculate "n", so that

n = molar mass of the molecular formula / molar mass of the empirical formula

The molar mass of the molecular formula is 150 g/mol.

The molar mass of the empirical formula is 12 + 2 × 1 + 16 = 30 g/mol

n = (150 g/mol) / (30 g/mol) = 5

Then, we multiply the empirical formula by 5.

CH₂O × 5 = C₅H₁₀O₅

7 0
3 years ago
For the reaction 3ZnCO3 + 2H3PO4 —> 3H2O + 3CO2, how many miles of zinc carbonate are required to produce 3.0 mil of Zn3(PO4)
drek231 [11]

Answer:

\boxed{ \text{9.0 mol of ZnCO$_{3}$}}

Explanation:

(a) Balanced equation

3ZnCO₃ + 2H₃PO₄  ⟶ Zn₃(PO₄)₂ + 3H₂O + 3CO₂

(b). Calculation

You want to convert moles of Zn₃(PO₄)₂  to moles of ZnCO₃

The molar ratio is 1 mol Zn₃(PO₄)₂:3 mol ZnCO₃  

\text{Moles of ZnCO$_{3}$} =\text{3.0 mol Zn$_{3}$(PO$_{4})_{2}$ } \times \dfrac{\text{3.0 mol ZnCO$_{3}$}}{\text{1 mol Zn$_{3}$(PO$_{4}$)$_{2}$}} \\\\\\= \text{9.0 mol ZnCO$_{3}$}

You need \boxed{ \textbf{9.0 mol of ZnCO$_{3}$}} to form 3.0 mol of Zn₃(PO₄)₂.

4 0
3 years ago
1. How many moles are in 3.01 x 10^23 molecules of Boron trichloride
marishachu [46]

Answer: There are 0.499 moles present in 3.01 \times 10^{23} molecules of Boron trichloride.

Explanation:

According to mole concept, there are 6.022 \times 10^{23} molecules present in 1 mole of a substance.

Hence, number of moles present in 3.01 \times 10^{23} molecules are as follows.

Moles = \frac{3.01 \times 10^{23}}{6.022 \times 10^{23}}\\= 0.499 mol

Thus, we can conclude that there are 0.499 moles present in 3.01 \times 10^{23} molecules of Boron trichloride.

6 0
3 years ago
A biochemist conducted an experiment to follow the movement of glucose molecules in animal cells. Glucose with radioactively lab
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Answer:

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Explanation:

This explanes all of what you need along with helpful videos an other things I found intersting for you HOPE IT HELPS YOU YOUR WELCOME.

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What is the word equation for sodium polyacrylate and water?
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3 years ago
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