Answer:
14.91 K.
Explanation:
- To solve this problem, we can use the following relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat transferred to water.
m is the mass of the amount of water (m = 2.0 kg = 2000.0 g).
c is the specific heat capacity of water (c = 4.2 J/g.K).
ΔT is the change in temperature due to the transfer of butane burning.
- To determine Q that to be used in calculation:
Q from 4.000 g of butane is completely burned is - 198.3 kJ = 198300 J.
<em>The negative sign</em><em> symbolizes the the enthalpy change is </em><em>exothermic</em><em>, which means that </em><em>the</em><em> </em><em>energy is released</em><em>.
</em>
- Note that only 63.15% of the energy generated is actually transferred to the water.
∴ Q (the amount of heat transferred to water) = (198300 J)(0.6315) = 125226.45 J.
- Now, we can obtain the change in temperature:
∴ ΔT = Q/m.c. = (125226.45 J) / (2000.0 g)(4.2 J/g.K) = 14.9079 K ≅ 14.91 K.
<em>This means that the temperature is increased by 14.91 K.</em>
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The snake,raccoon, and preying mantis
Answer:
Explanation:
As one moves down the vertical groupings of elements on the periodic table, it is evident that new shells are being added from top to down.
An atomic orbital is the region of space surrounding the nucleus where there is a high probability of finding an electron.
Down a group, the atomic radius increases as more shells are added to an atom.
I think the correct answer would be C. The common characteristic that is shareed by the elements found at the center of a period would be that they are the least reactive species. Having lower value of electronegativity, there is less ionization of the atoms which would also contribute to less reactivity.
