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3 years ago

Solve for X: 125^x = 25^(x+2)

Mathematics

1 answer:

creativ13 [48]3 years ago

4 0

X=4

5^3=125 5^2=25

5^3x= 5^2(x+2)
3x=2x+4
x=4

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Alternatively: We could also calculate the critical value to obtain +1.685 for $\alpha=0.05$ and d.f=39 and compare to the test-value:

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