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statuscvo [17]
3 years ago
9

What is -7 equals 3 + K

Mathematics
2 answers:
ki77a [65]3 years ago
5 0
-10=k is going to be your answer
alexgriva [62]3 years ago
4 0
The will be -10 !!!!
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A right rectangular prism has a length of 214 cm, width of 8 cm, and height of 2012 cm.
Amiraneli [1.4K]
The volume is 214*8*2012
=3,444,544
4 0
3 years ago
Little Joey can finish carpeting ½ of a room in ¼ of an hour. At this rate, how many rooms can he carpet in 1 hour?
mezya [45]

Answer:

2 rooms

Step-by-step explanation:

1/2 divided by 1/4 is 2

2 times 1 = 2

Answer - 2

5 0
3 years ago
Solve the triangle.
vova2212 [387]

9514 1404 393

Answer:

  b = 71 m

  A = 83°

  C = 29°

Step-by-step explanation:

Many calculators can solve triangles. Apps are available for phone and tablet, or on the internet, like the one used here. In general, it takes less time to use one of these than to type your question into Brainly.

Given two sides and the angle between them, the Law of Cosines is the appropriate relation to use for finding the third side.

  b = √(a² +c² -2ac·cos(B))

  b = √(76² +37² -2·76·37·cos(67.75°)) ≈ √5015.48

  b ≈ 70.82005 ≈ 71 . . . meters

__

One a side and its opposite angle are known, the remaining angles are found using the Law of Sines.

  sin(A)/a = sin(B)/b

  A = arcsin(a·sin(B)/b) = arcsin(76·sin(67.75°)/70.82005) ≈ 83.33°

  A ≈ 83°

  C = arcsin(37·sin(67.75°)/70.82005) ≈ 28.92°

  C ≈ 29°

Or, you can find the remaining angle from 180° -68° -83°  = 29°.

3 0
3 years ago
5/6 - 1/2 = ?<br><br>A. 1/4<br><br>B. 1/3<br><br>C. 3/4<br><br>D. 2/3<br>​
zheka24 [161]
5. . 1
---- - -----
6. . 2


5. . 3
----- - -----
6. . 6


5-3
-------
6

2
-----
6


= 1/3

B
3 0
3 years ago
Find the values of λ for which the determinant is zero.
elena55 [62]

Answer:

Determinant are special number that can only be defined for square matrices.

Step-by-step explanation:

Determinant are particularly important for analysis. The inverse of a matrix exist, if the determinant is not equal to zero.

How to find determinant

For a 2×2 matrix

det ( \left[\begin{array}{cc}x&y\\a&z\end{array}\right] ) = xz-ay

For a 3×3 matrix

we first decompose it to 2×2

det (\left[\begin{array}{ccc}k&l&m\\o&p&q\\r&s&t\end{array}\right] )\\\\= k*det(\left[\begin{array}{cc}p&q\\s&t\end{array}\right] ) - l*det(\left[\begin{array}{cc}o&q\\r&t\end{array}\right] ) + m*det(\left[\begin{array}{cc}o&p\\r&s\end{array}\right] ) \\\\=k(pt-sq) - l(ot-rq) + m(os-rp)

Example

Find the values of λ for which the determinant is zero

\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right]

det(\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right])\\\\= s*det(\left[\begin{array}{cc}s&-1\\-1&1\end{array}\right] ) - (-1)*det(\left[\begin{array}{cc}-1&-1\\0&1\end{array}\right] ) + 0*det(\left[\begin{array}{cc}-1&s\\0&-1\end{array}\right] )\\\\= s(s(1)-(-1*-1)) - (-1)(-1*1 - (-1*0)) + 0\\= s(s - 1)) + 1(-1 + 0) \\=s^{2} -s-1

Equating the determinant to zero

s^{2} -s-1 =0\\

s = \frac{1}{2} * (1 ±5 )

s = 1.61 or -0.61

5 0
3 years ago
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