What causes pressure inside a bicyle tire?

Without consulting Figure 28 or Table 22, determine whether each of the following electron configurations is an inert gas,a halo

Anna [14]

This is an incomplete question, here is a complete question.

Determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices.

(a) $1s^22s^22p^63s^23p^5$

(b) $1s^22s^22p^63s^23p^63d^74s^2$

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$

(d) $1s^22s^22p^63s^23p^64s^1$

(e) $1s^22s^22p^63s^23p^63d^24s^2$

(f) $1s^22s^22p^63s^2$

Answer :

(a) $1s^22s^22p^63s^23p^5$ → Halogen

(b) $1s^22s^22p^63s^23p^63d^74s^2$ → Transition metal

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$ → Transition metal

(d) $1s^22s^22p^63s^23p^64s^1$ → Halogen metal

(e) $1s^22s^22p^63s^23p^63d^24s^2$ → Transition metal

(f) $1s^22s^22p^63s^2$ → Alkaline earth metal

Explanation :

Inert gas : These are the gases which lie in group 18.

Their general electronic configuration is: $ns^2np^6$ where n is the outermost shell.

Halogen : These are the elements which lie in group 17.

Their general electronic configuration is: $ns^2np^5$ where n is the outermost shell.

An alkali metal : These are the elements which lie in group 1.

Their general electronic configuration is: $ns^1$ where n is the outermost shell.

An alkaline earth metal : These are the elements which lie in group 2.

Their general electronic configuration is: $ns^2$ where n is the outermost shell.

Transition elements : They are the elements which lie between 's' and 'p' block elements. These are the elements which lie in group 3 to 12. The valence electrons of these elements enter d-orbital.

Their general electronic configuration is: where n is the outermost shell.

(a) $1s^22s^22p^63s^23p^5$

The element having this electronic configuration belongs to the halogen family.

(b) $1s^22s^22p^63s^23p^63d^74s^2$

The element having this electronic configuration belongs to the transition family.

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$

The element having this electronic configuration belongs to the transition family.

(d) $1s^22s^22p^63s^23p^64s^1$

The element having this electronic configuration belongs to the halogen family.

(e) $1s^22s^22p^63s^23p^63d^24s^2$

The element having this electronic configuration belongs to the transition family.

(f) $1s^22s^22p^63s^2$

The element having this electronic configuration belongs to the an alkaline earth metal.

7 0

3 years ago

Which of the following diagrams best represents a mixture?

Travka [436]

D. I hope i helped ;)

3 0

3 years ago

Read 2 more answers

The pressure of a gas sample was measured to be 654 mmhg. What is the pressure in kpa? (1 atm = 1. 01325 × 10 5 pa)

Stels [109]

Taking into account the change of units, the pressure of the gas sample is 87.19 kPa.

<h3>What is rule of three</h3>

In first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: $c=\frac{cxb}{a}$

<h3>Pressure</h3>

The direct rule of three is the rule applied in this case where there is a change of units.

To perform in this case the conversion of units, you must first know that:

1 atm= 760 mmHg
1 atm = 1. 01325×10⁵ Pa= 101325 Pa
1 kPa= 1000 Pa

So, if 1 atm is 760 mmHg, how many atm equals 654 mmHg?

760 mmHg ⇒ 1 atm

654 mmHg ⇒ x

So: $x=\frac{654 mmHgx1 atm}{760 mmHg}$

Solving:

Now, if 101325 Pa are 1 atm, how many Pa equals 0.86 atm?

1 atm ⇒ 101325 Pa

0.86 atm ⇒ x

So: $x=\frac{0.86 atmx101325 Pa}{1 atm}$

Solving:

Finally, if 1 kPa is 1000 Pa, how many kPa equals 87,192.83 Pa?

1000 Pa ⇒ 1 kPa

87,192.83 Pa ⇒ x

So: $x=\frac{87,192.83 Pax1 kPa}{1000 Pa}$

Solving:

In summary, the pressure of the gas sample is 87.19 kPa.

Learn more with this example:

brainly.com/question/12482948

#SPJ12

5 0

2 years ago

How many moles of copper are present in 75.0g Cu? Show your complete calculation and give the answer in the correct number of si

velikii [3]

Answer:

The answer to your question is 1.2 moles of copper

Explanation:

Data

mass of copper = 75 g

moles = ?

Process

1.- Look in the periodic table for the atomic mass of copper.

Atomic mass = 63.55 g/mol

2.- Use proportions to determine the moles of copper in 75 g

63.55 g of copper -------------------- 1 mol

75 g of copper -------------------- x

Use cross multiplication

x = (75 x 1) / 63.55

x = 75 / 63.55

x = 1.18 moles ≈ 1.2 moles of copper

3 0

4 years ago

Read 2 more answers

Compared to the physical and chemical properties of the compound NO2, the compound N2O has

Lelu [443]

Answer:

B

Explanation:

The two compounds have different physical properties and different chemical properties despite the fact that they are formed from nitrogen and oxygen.

8 0

4 years ago