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mylen [45]
3 years ago
14

Which acid and base react in the formation of salt sodium chloride? hydrochloric acid and sodium hydroxide sodium carbonate and

chlorine sodium hydroxide and sodium chloride
Chemistry
1 answer:
malfutka [58]3 years ago
7 0
Hydrochloric acid and sodium hydroxide

HCl + NaOh ----> NaCl + H2O
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Which substance is the oxidizing agent in this reaction? fe2o3+3co→2fe+3co2 express your answer as a chemical formula?
erma4kov [3.2K]
Equation is as follow,

                            Fe₂O₃  +  3 CO     →     2 Fe  +  3 CO₂

Oxidation:

                                        3 CO     →     3 CO₂

Oxidation state of C in CO is +2, and that in CO₂ is +4. So, carbon has lost 2 electrons per mole and 6 electrons per 3 moles hence,

                                 3 CO     →     3 CO₂  +  6 e⁻

Reduction:

                                    Fe₂O₃     →     2 Fe

Oxidation state of Fe in Fe₂O₃ is +3 per atom, and that in Fe is 0. So, Iron has gained 3 electrons per atom and 6 electrons per 2 atoms hence,

                                    Fe₂O₃  +  6e⁻     →     2 Fe

Result:
             Iron in Fe₂O₃ has been reduced in this reaction and has played a role of oxidizing agent by oxidizing carbon from +2 state to +4 state.
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How long would it take for Hydrogen Peroxide to break down naturally (without an enzyme)
iogann1982 [59]

Answer:

Hydrogen peroxide is a very pale blue liquid at room temperature. A French scientist called Louis Auguste Thenard discovered the compound in 1818. Hydrogen peroxide can easily break down, or decompose, into water and oxygen by breaking up into two very reactive parts – either 2OHs or an H and HO2:

Explanation:

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2 years ago
What does the law of convservation of matter show?​
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3 0
3 years ago
_AI + _HCI —> _H2 + _AlCl3
SOVA2 [1]

Hey there!

Al + HCl → H₂ + AlCl₃

Balance Cl.

1 on the left, 3 on the right. Add a coefficient of 3 in front of HCl.

Al + 3HCl → H₂ + AlCl₃

Balance H.

3 on the left, 2 on the right. We have to start by multiplying everything else by 2.

2Al + 3HCl → 2H₂ + 2AlCl₃

Now we have 2 on the right and 4 on the left. Change the coefficient in front of HCl from 3 to 4.

2Al + 4HCl → 2H₂ + 2AlCl₃

Now, for Cl, we have 4 on the left and 6 on the right. Change the coefficient in front of HCl again from 4 to 6.

2Al + 6HCl → 2H₂ + 2AlCl₃

Now, our H is unbalanced again. 6 on the left, 4 on the right. Change the coefficient in front of H₂ from 2 to 3.

2Al + 6HCl → 3H₂ + 2AlCl₃  

Balance Al.

2 on the left, 2 on the right. Already balanced.

Here is our final balanced equation:

2Al + 6HCl → 3H₂ + 2AlCl₃  

Hope this helps!

7 0
3 years ago
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