Solve sin^2 2θ=-1-cos^2θ on the interval 0<θ<2pi
1 answer:
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Hello,
Let's x² the square number
and 3*y the multiple of 3.
2 solutions : for (x,y) as integers : (-6,18) and (6,18)
but one solution for (x²,3y) as integers :<u> (36,54) </u>
