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Amiraneli [1.4K]
3 years ago
8

Given g(x) = -4c – 2, find g(-2).

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

g(x) = 4c - 2.

g(-2) = 4(-2) - 2

g(-2) = 8 - 2

g(-2) = 6.

Oliga [24]3 years ago
3 0

\\ \sf\longmapsto g(x)=-4c-2

Then

\\ \sf\longmapsto g(-2)

\\ \sf\longmapsto -4(-2)-2

\\ \sf\longmapsto 8-2

\\ \sf\longmapsto 6

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5x+15+10x+7<br><br> 5(x+3)+2x+7
Marta_Voda [28]

Step-by-step explanation:

<u>1. Combine Like Terms (Add):</u>

5x+15+10x+7

15x+22

<u>2. Use Distributive Property:</u>

<u />5(x+3)+2x+7

5x+15+2x+7

<u>Combine Like Terms:</u>

7x+22

5 0
2 years ago
Please help <br> wahat is the slope of the line !?!?
shepuryov [24]
There are two methods
1. Find any two points
(1,2) and (2,4)
(4-2)/(2-1) = 2/1 = 2

2. When x = 1, y = 2
The unit rate goes up by 2

The slope is 2 :)
6 0
3 years ago
Choose what you think the expressions below best represent within the context of the word problem. A man traveled a certain numb
irina1246 [14]

X represents miles by <u>automobile</u>

9x represents miles by <u>airplane</u>


Hope this helps!!!

5 0
3 years ago
Read 2 more answers
According to this diagram what is tan 62
kicyunya [14]

The figure is not attached. So, I have attached it from the link- brainly.com/question/4198293

Answer:

\tan(62)=1.875

Step-by-step explanation:

Label the triangle ABC as shown below.

Given:

AB = 8, BC = 15, AC = 17, m∠ABC = 90°, m∠ACB = 28°, m∠BAC = 62°

The tangent of a given angle is given as the ratio of the opposite side and the adjacent side. The opposite side is the side opposite to the angle. The adjacent side is the other leg of the right angled triangle.

Here, the opposite side to angle A is BC and adjacent side is AB.

Therefore, the tan ratio of angle A is given as:

\tan A=\frac{BC}{AB}\\\tan (62)=\frac{15}{8}=1.875

Hence, tan 62 = 1.875.

4 0
4 years ago
The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the
nignag [31]

Assuming that by "16t2" you mean 16t^2:


First of all, let's compute the position at the two required times:


d(2)=16\cdot 2^2 = 16*4 = 64


d(5)=16\cdot 5^2 = 16*25 = 400


So, the ball traveled a total distance of \Delta d = 400-64 = 336, during the time \Delta t = 5-2 = 3.


The average rate of change is the ratio between these two:


\frac{\Delta d}{\Delta t} = \frac{336}{3} = 112

3 0
3 years ago
Read 2 more answers
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