Step-by-step explanation:
Calcium carbonate reacts w/stomach acid according to the following chemical equation.
CaCO3+2HCl(aq)-> CaCl2(aq)+H2O(l)+CO2(g)
It’s C. I have to put more letters just ignore this
The answer is -20 and you solve by putting it in the calculator
Huh??? Where is the question?
Answer:
The frequency of the note a perfect fifth below C4 is;
B- 174.42 Hz
Step-by-step explanation:
Here we note that to get the "perfect fifth" of a musical note we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have
1.5 × Frequency of note Y = Frequency of C4
1.5 × Y = 261.63
Therefore, Y = 261.63/1.5 = 174.42 Hz.
