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Kazeer [188]
4 years ago
10

Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = -1

Mathematics
1 answer:
NeX [460]4 years ago
8 0
From the given information, the parabola is a regular parabola facing up with vertex at (-5, 2).
Required equation is (x + 5)^2 = 4p(y - 2)

But 2 + p = 5 => p = 5 - 2 = 3

Therefore, required equation is (x + 5)^2 = 4(3)(y - 2)
(x + 5)^2 = 12(y - 2)
y - 2 = 1/12 (x + 5)^2
y = 1/12 (x + 5)^2 + 2
f(x) = 1/12 (x + 5)^2 + 2
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Answer:

7m

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Let m be the miles he jogs each day

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Grade 7 students were surveyed to determine how many hours a day they spent, on average, doing various activities. The results a
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Hello,

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lutik1710 [3]

Given:ABCD is a rhombus.

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In rombus, we know opposite angle are equal.

so, angle DCB = angle BAD

SINCE, ANGLE DCB= BAD

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angle DCA=angle DAC

similarly, In triangle ABC

angle BAC=angle BCA

since angle BCD=angle BAD

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so,sides DC=BC

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2ANGLE CED=ANGLE CEB (DC=BC)....(A)

3.CE=CE (common sides)(S)

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andrezito [222]

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Step-by-step explanation:

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