Answer:
the answer is one
Step-by-step explanation:
1.......
The options 2 and 4 would have the same graphical representation.
Step-by-step explanation:
Step 1:
To determine which functions are equal to the question, we must assign values to x and see which values equal the function f(x) =
.
Any random value can be assigned to x but the same value of x must be assigned to all the equations.
Step 2:
If we substitute x = 5, we get
Question; f(x) = ![16.2^{x} = 16.2^{5}= 16.(32) = 512.](https://tex.z-dn.net/?f=16.2%5E%7Bx%7D%20%3D%2016.2%5E%7B5%7D%3D%2016.%2832%29%20%3D%20512.)
Option 1; f(x) ![= 4.4^{x} = 4.4^{5} = 4.(1,024)= 4,096.](https://tex.z-dn.net/?f=%3D%204.4%5E%7Bx%7D%20%3D%204.4%5E%7B5%7D%20%3D%204.%281%2C024%29%3D%204%2C096.)
Option 2; f(x) = ![4.2^{x+2} = 4.2^{5+2} = 4.(128) = 512.](https://tex.z-dn.net/?f=4.2%5E%7Bx%2B2%7D%20%3D%204.2%5E%7B5%2B2%7D%20%3D%204.%28128%29%20%3D%20512.)
Option 3; f(x) = ![32^{x} = 32^{5} = 33,554,432.](https://tex.z-dn.net/?f=32%5E%7Bx%7D%20%3D%2032%5E%7B5%7D%20%3D%2033%2C554%2C432.)
Option 4; f(x) ![= \frac{1}{4}. 2^{x+6} = \frac{1}{4}. (2^{5+6}) =\frac{1}{4}. (2048) = 512.](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B4%7D.%202%5E%7Bx%2B6%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D.%20%282%5E%7B5%2B6%7D%29%20%3D%5Cfrac%7B1%7D%7B4%7D.%20%282048%29%20%3D%20512.)
So options 2 and 4 would have the same graphical representation.
Answer:
i'm not that smart or ANYTHIGN but i tried:
4f2inx
Step-by-step explanation:
The value of P in the expression
is 25
Given the expression ![x^2-10x+P=(x-A)(x-B)](https://tex.z-dn.net/?f=x%5E2-10x%2BP%3D%28x-A%29%28x-B%29)
To get the value of P, we will use the completing the square method;
Add the<u> square of the half of the coefficient of x</u>
- The coefficient of x is -10
- Half of the coefficient of x is -10/2 = 5
- Square of <u>half of the coefficient of x</u> = 5^2 = 25
Hence the complete quadratic expression will be ![x^2-10x + 25](https://tex.z-dn.net/?f=x%5E2-10x%20%2B%2025)
Hence the value of P in the expression
is 25
Learn more here: brainly.com/question/13981588