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Yanka [14]
3 years ago
14

Simplify

Mathematics
1 answer:
melomori [17]3 years ago
4 0

Answer: 4\sqrt{3}

Step-by-step explanation:

For this exercise it is important to remember the following:

i=\sqrt{-1} \\\\i^2=-1

Given the following expression:

-2i\sqrt{-12}

You can notice that the radicand (the number inside the square root) is negative. Therefore, in order to simplify the expression, you need to follow these steps:

1. Replace \sqrt{-1} with i and simplify:

(-2i)(i)\sqrt{12}=-2i^2\sqrt{12}=-2(-1)\sqrt{12}=2\sqrt{12}

2. Descompose 12 into its prime factors:

12=2*2*3=2^2*3

3. Substitute into the expression:

=2\sqrt{2^2*3}

4. Since \sqrt[n]{a^n}=a, you can simplify it:

=(2)(2)\sqrt{3}=4\sqrt{3}

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check the picture below.

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it cannot be -1, because is a seconds amount after moving.

8 0
4 years ago
Find f^-1(x) for f(x) = 1/x^3
kow [346]

Answer: f^{-1}(x) = \frac{\sqrt[3]{x^{2}}}{x}

<u>Step-by-step explanation:</u>

y = \frac{1}{x^{3}}

Inverse is when you swap the x's and y's and then solve for "y":

x = \frac{1}{y^{3}}

y^{3} = \frac{1}{x}

y = \frac{1}{\sqrt[3]{x}}

y = \frac{1}{\sqrt[3]{x}}*(\frac{\sqrt[3]{x}}{\sqrt[3]{x}})^{2}

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4 0
3 years ago
help me please, this is due tomorrow ( The circumference of a circle is 53.38 centimeters. What is the area in square centimeter
g100num [7]

Step-by-step explanation:

C = 2πr = 53.38cm

r = C / 2π = 53.38cm / 2π = 53.38/ 6.283185307179586 = 8.4956cm

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7 0
2 years ago
Which ordered pair is the solution to the system of equations? {y=x−4−4x+3y=−3 (−9, −13)
Leviafan [203]
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p.s I already took the test and this was right
hope I helped :)
8 0
3 years ago
there are three exams in a marking period. A student received grades of 75 and 81 on the first two exams. What grade must the st
gulaghasi [49]

Answer: average means add all scores and divide by number of scores earned

last score is x

so the sum is 75+81+x

3 scores so (75+81+x)/3=average

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(75+81+x)/3≥80

solve

times both sides by 3 to clear fraction

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156+x≥240

minus 156 from both sides

x≥84

the studen must earn at least 84 on last exam

Step-by-step explanation:

6 0
3 years ago
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