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2 years ago

Randy is twice as old as his sister jane. together the sum of their ages is 15. how old is randy?

1 answer:

8 0

The sum is 15.
Divide 15 by three to get Jane's age= 5
The remainder, which is J * 2, or ten, is Randy's age.
Randy is ten.

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-2=3(y-2) how do you solve this problem for y

Ksivusya [100]

Answer:

y= 4/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−2=3(y−2)

−2=(3)(y)+(3)(−2)(Distribute)

−2=3y+−6

−2=3y−6

Step 2: Flip the equation.

3y−6=−2

Step 3: Add 6 to both sides.

3y−6+6=−2+6

3y=4

Step 4: Divide both sides by 3.

3y /3 = 4 /3

y= 4/3

Answer:

y= 4/3

8 0

2 years ago

Bob took 20 math test last year if he failed 6 of them what percent of the math test did he pass

kodGreya [7K]

6 out of 20=what percent?
6/20=x%

percent means parts out of 100
x%=x/100

6/20=x/100
time both sides by 100
30=x
answer is 30% passed

100-30=70
70% is answer

8 0

2 years ago

Read 2 more answers

Serjik [45]

Answer:

Probability that a customer pays the bill by mail, given that the customer is female is 0.20.

Step-by-step explanation:

The complete question is:

Online By Mail Total

Male 12 8 20

Female 24 6 30

Total 36 14 50

A utility company asked 50 of its customers whether they pay their bills online or by mail. What is the probability that a customer pays the bill by mail, given that the customer is female.

Probability that a customer pays the bill by mail, given that the customer is female is given by = P(Pays bill by mail / Customer is female)

$\frac{6}{50}$ P(Pays bill by mail/Customer is female) = $\frac{P(\text{Pays bill by Mail}\bigcap \text{ Customer is Female})}{P(\text{ Customer is Female})}$

Now, Probability that customer is female = $\frac{30}{50}$

Also, Probability that customer pays bill by mail and is female = $\frac{6}{50}$

So, Required probability = $\frac{\frac{6}{50} }{\frac{30}{50} }$

= $\frac{6}{50}\times \frac{50}{30}$

= $\frac{1}{5}$ = 0.20

Hence, probability that a customer pays the bill by mail, given that the customer is female is 0.20.

6 0

2 years ago

Solve the inequality y/ -6 is greater than 10

pashok25 [27]

Y<-60
hope this helps and good luck;)

4 0

3 years ago

In the square below, the two semi-circles are congruent. Find the area of the shaded region. If necessary, round your answer to

Jobisdone [24]

Let's start with the area of the square
$area \: square = s \times s = 8 \times 8 = 64$
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

$area \: circle = \pi {r}^{2} = \pi \times {4}^{2} = 16\pi$
now we just subtract and our answer is

$64 - 16\pi = 64 - 16 \times (3.14) = 13.73$

3 0

3 years ago