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Liono4ka [1.6K]
3 years ago
7

Marco can finish a jigsaw puzzle in 3 hours. Working together with Cliff, it takes them 1 hour. How

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

Macro can finish the puzzle in 3 hours. We can say that her speed for working is 1/3 or 1/3 puzzle per hour.

Now if they work together, this turns into 1 puzzle per hour.

That must mean that Cliff would be doing the other 2/3 of the puzzle while Macro does his 1/3 in that hour. If Cliff has a speed of doing them 2/3 per hour. Then it would take 1 and a half hour to finish 1 whole puzzle.

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Which point is a solution to the system of equations graphed below?
UkoKoshka [18]
C.

This is because the x vale is clearly after the 6 and the y value is right on 5 
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A can holds 2 liters of paint.<br><br>then how many can we fill with 11 liters of paint​
pychu [463]

Answer:

5 and a half

Step-by-step explanation:

Because you can fit 2 liters in each can, to find how many you would need, divide 11 by 2, this would give you 5 and a half, 5.5.

It could be that they want you to round up to six or round down to five, so do consider that.

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3 years ago
F(x)=3.7-2x
Luda [366]

Answer:

C) h(x)=-1.3-1.75x

Step-by-step explanation:

f(x)=3.7-2x  

g(x) = 0.25x-5

f(x) + g(x) =3.7-2x   + 0.25x-5

Combine like terms

              = -1.75x - 1.3

5 0
3 years ago
Susannah has a high-yield savings account into which she deposits $140 each month. At the beginning of the year, Susannah's acco
motikmotik

Answer:

Her account balance will be $2,080 at the end of the year

Step-by-step explanation:

Let

y ----> Susannah's account balance

x ---> is the  amount of time in months

we have

y=140x+400

This is a linear equation in slope intercept form

where

The slope or unit rate is equal to

m=\$140\ per\ month

The y-intercept or initial value is equal to

b=\$400

Remember that

One year is equal to 12 months

so

For x=12 months

substitute in the linear equation

y=140(12)+400=\$2,080

5 0
3 years ago
A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li
svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

15 drivers are randomly selected, so n = 15.

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year.  This means that \pi = 0.08.

What is the probability of getting 3 or more who were involved in a car accident last year?

This is P(X \geq 3).

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

P(X < 3) + P(X \geq 3) = 1

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{15,0}.(0.08)^{0}.(0.92)^{15} = 0.2863

P(X = 1) = C_{15,1}.(0.08)^{1}.(0.92)^{14} = 0.3734

P(X = 2) = C_{15,2}.(0.08)^{2}.(0.92)^{13} = 0.2273

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2863 + 0.3734 + 0.2273 = 0.887

Finally

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.887 = 0.113

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

5 0
3 years ago
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