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Leokris [45]
3 years ago
12

If a person can carry 40 pounds, and a group of people want to carry 86 pounds of stuff, how many people are necessary to carry

the 86 pounds of stuff?
Please help?
Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

3 people

Step-by-step explanation:

Because 40+40 =80 also equals 2 people so if they can only do 80 together then you would need another person even if its 6 more pounds then 80.

Hope this helps....Also please like if this helped you so I know to do more!!! :)

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What is the vertex of f (x) = 5x^2+20x-16
sergeinik [125]

Answer:

vertex = (- 2, - 36)

Step-by-step explanation:

Given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

f(x) = 5x² + 20x - 16 is in standard form

with a = 5, b = 20 and c = - 16

x_{vertex} = - \frac{20}{10} = - 2

Substitute x = - 2 into f(x) for corresponding y- coordinate

f(- 2) = 5(- 2)² +20(- 2) - 16 = 20 - 40 - 16 = - 36

vertex = (- 2, - 36)



3 0
2 years ago
Read 2 more answers
A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
Please help with my guided practice ​
qaws [65]

it's 88 I've been getting so mix up forgive me So the area of the square is 64. When you find the area of the triangle you multiply the base by its height, which is 6 by 8 and then you divide by two. 64+24=88

7 0
2 years ago
CAN SOMEONE HELP PLEASE!!
grandymaker [24]
The predicted time remaining has decreased by 30 years, so the second one would be the answer
3 0
3 years ago
Helpppppppppp ASAP pls and thankyouu
natima [27]

Answer:

1. The graph of the inequality, y > -3·x - 2, created with MS Excel is attached showing the following characteristics;

Linear

Shade is above the line

2.  The graph of the inequality, y ≤ │x│ - 3,  created with MS Excel is attached showing the following characteristics

Linear

Shade is below the line

3. The graph of the inequality, y < x² - 4,  created with MS Excel s attached showing the following characteristics;

Quadratic

Shade below the line

Step-by-step explanation:

8 0
2 years ago
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