Answer:
1. a + b + c = 180
2. b + d = 180
3. d = a + c
Step-by-step explanation:
1. a + b + c = 180:
Angles in a triangle add up to 180
2. b + d = 180:
Angles in a straight line equal 180 because they are supplementary angles
3. d = a + c:
ΔACD is an exterior angle, and ΔACB is interior adjacent, hence ∠a and ∠c add up to ∠d
Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
The height of the antenna on the roof of the local building is approximately 8 meters.
The situation forms a right angle triangle.
<h3>Properties of a right angle triangle:</h3>
- One of its angles is equals to 90 degrees
- The sides of the triangles can be calculated using Pythagoras theorem.
Therefore, let's find the height of the building and the radio antenna from the eye point.
Using trigonometric ratios,
tan 40° = opposite / adjacent
tan 40° = x / 25
where
x = the height of the building and the radio antenna from the eye point.
x = 25 tan 40
x = 25 × 0.83909963117
x = 20.9774907794 meters
Let's find the height of the building from his eye point.
tan 28° = y / 25
where
y = height of the building from his eye point
y = 25 × tan 28°
y = 25 × 0.53170943166
y = 13.2927357915 meters
Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786
Height of the antenna ≈ 8 meters
learn more on elevation here: brainly.com/question/17582385?referrer=searchResults
