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lesya [120]
3 years ago
6

Please will anyone help me out with this math problem? I will give them a crown.

Mathematics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

a. 450 b.  10078.9097

Step-by-step explanation:

a. go with the formula W=FD

F= force

W= work done

D= distance

b. go with the formula F=mgcos(x)

M= mass

G= gravity constant (9.8)

then get to the normal formula of W=FD after getting the Force

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Answer:

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Step-by-step explanation:

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What is the arc length if Θ = 2 pi over 7 and the radius is 3 cm? A. 7 pi over 12
hodyreva [135]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

\theta=\frac{2\pi}{7} \\\\r=3\ cm

An arc is a part of total circumference of circle and length of that arc is the measurement of linear distance.

Since we know the formula for "Length of an arc " , we get

L=r\times \theta\\\\L=\frac{2\pi}{7}\times 3\\\\L=\frac{6\pi}{7}

Hence, Option 'C' is correct.


6 0
3 years ago
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Find the sum of the following series. Round to the nearest hundredth if necessary,
Aneli [31]

Answer:

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3 0
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Please help this is timed
elena-14-01-66 [18.8K]

Answer:

option d is correct

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6 0
3 years ago
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(b) dy/dx = (x - y+ 1)^2
Elanso [62]

Substitute v(x)=x-y(x)+1, so that

\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}

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On the left, we can split into partial fractions:

\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx

Integrating both sides gives

\dfrac{\ln|1-v|+\ln|1+v|}2=x+C

\dfrac12\ln|1-v^2|=x+C

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v=\pm\sqrt{1-Ce^{2x}}

Now solve for y(x):

x-y+1=\pm\sqrt{1-Ce^{2x}}

\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}

3 0
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