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Lemur [1.5K]
3 years ago
6

Linear relations are not functions when they appear graphically as:

Mathematics
1 answer:
hoa [83]3 years ago
4 0
<span>Linear relations are not functions when they appear graphically as:
Vertical lines

One  x  not  one y</span>
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Graph: y=|x - 4| + 2
kramer

Answer:

See attached graph.

Step-by-step explanation:

We can graph this with relative ease on the calculator or computer (see attachment) but let's make sure we understand it theoretically and algebraically!

y=|x - 4| + 2

First of all, this is an absolute value function, so it'll look like a v where every input equals its positive output (2, 2) (-3,3) etc. You can't get a negative number with a graph of y=|x| unless you translate it.

Next, there's a -4 inside the abs val. According to the formula y = |x - h| + k, where h is the horizontal shift, this means we need to shift the vertex right 4.

There's a +2 outside the abs val. K is the vertical shift, so we need to shift the vertex up 2.

3 0
3 years ago
Read 2 more answers
Can someone please help
TEA [102]

Answer:

All real numbers

Step-by-step explanation:

The domain represents the x-coordinates, so you can see on the graph that it goes all the way out to both the left and right directions, meaning it covers all the negative numbers, and all the positive numbers. The question is trying to trick you into thinking about the range, but forget about the y-axis for this one.

6 0
2 years ago
Read 2 more answers
Sally’s wallet contains:
Sonbull [250]

Answer:

Nickles: 96 times

Penny:  48 times

Step-by-step explanation:

5+3+8+4 = 20 coins in total

20x = 240

x=12 (chance of a coin being picked)

8 nickles(12) = 96

4 pennies(12) = 48

4 0
3 years ago
Read 2 more answers
What does the expression “a red rag to the bull” suggest?
Eva8 [605]
The last resort because you have no more options
5 0
3 years ago
Solve the following systems by substitution
Paladinen [302]

Answer:

The answer to your question is below

Step-by-step explanation:

Question 1

                x = 5                       Equation l

                2x + y = 10              Equation ll

- Substitute Equation l in equation ll

               2(5) + y = 10

                y = 10 - 10

                y = 0

- Solution  (5, 0)

Question 2

                 x + 16y = 20          Equation l

                 x = 4y                    Equation ll

Substitute equation ll in equation l

                4y + 16y = 20

                        20y = 20

                           y = 20/20

                           y = 1

-Find x

                x = 4(1)

                x = 4

-Solution

                (4, 1)

Question 3

                   2x + 8y = 20            Equation l

                     x = 2                       Equation ll

-Substitute equation ll in equation l

                   2(2) + 8y = 20

                      4 + 8y = 20

                            8y = 20 - 4

                            8y = 16

                              y = 16/8

                              y = 2

- Solution

                   (2, 2)              

8 0
3 years ago
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