Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
IT SHOULD BE 24 IF NOT IM SRRY
___-1=10-3
x-1=10-3
x-1=7
x=8
therefore the blank is 8
Step-by-step explanation:
[ Refer to the attached file ]
( Slide to refer all files )
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• To solve Questions of type 11 we need to simplify the equation by using mathematical operations !!
• To solve Questions of type ( 13 , 15 and 17 ) we try to make the bar numeral to come other side of decimal
° and by subtracting we get the required fraction !!
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