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schepotkina [342]
3 years ago
15

HELP ME ASAP TO DO THE MATH

Mathematics
1 answer:
yulyashka [42]3 years ago
8 0

Answer:

A = pi*(8 mm)^2 = 64*pi mm^2

Step-by-step explanation:

The formula for the area of a circle is A = pi*r^2, where r is the radius.  Thus, r^2 = (25pi) / pi, or 25, and r = 5 mm.

If we increase this radius by 3 mm, we get the new radius 8 mm.  The area of the new circle will thus be A = pi*r^2, or, in this particular case,

A = pi*(8 mm)^2 = 64*pi mm^2.

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Find the surface area of the sphere with the given dimension. Leave your answer in terms of π. Sphere with radius of 60 m.
prohojiy [21]
The surface area of a sphere is given by A=4 \pi  r^{2} where r represents the radius.

As the radius is given as 60 meters we replace r with 60 in the formula above to get the surface area.

A=4 \pi ( 60^{2} )=14400 \pi
6 0
2 years ago
Carmen ran 2 laps around the track in 6 minutes. What are the unit rates in laps per minute and minutes per lap?
Rudiy27
6/2 = 3 (minutes per lap)
3 0
2 years ago
The vertex of the parabola below is at the point (2,4), and the point (3,6) is
lukranit [14]

Answer:

A. y= 2(x - 2)2 + 4

Step-by-step explanation:

vertex having an x value of 2 means the phrase in paren must be x - 2.

This eliminates B and D

vertex having a y value of 4 is of no help as the remaining two equations will result in 4 if the x term is 2

plugging in x = 3 makes y = 6 in equation A, but not in equation C where y = 10

3 0
3 years ago
#1 Write each fraction as a decimal Indicate
antiseptic1488 [7]
Decimal Exact form: 25/6
It is a terminating decimal
5 0
3 years ago
25. A sequence of positive integers with 2020 terms is called an FT sequence if each term
lana66690 [7]

Answer:

The first term in the sequence is odd-valued and so there are m choices for it.2020 Gauss Contest Solutions Page 19

The second term in the sequence is even-valued and so there are m − 1 choices for it.

Thus, there are a total of m × (m − 1) FT sequences that begin with an odd-valued term

followed by an even-valued term.

Finally, we consider the FT sequences that begin with an even-valued term followed by an

odd-valued term (Parity #4).

Again, there are exactly twice as many odd-valued terms as there are even-valued terms in the

first 2019 terms (since the pattern repeats even, odd, odd).

However in this case, the 2020th term is even and so there are fewer than twice as many odd valued terms as there are even-valued terms.

Thus, there are m2 + m × (m − 1) FT sequences that satisfy the required conditions.

Since there are 2415 such FT sequences, we may solve m2 + m × (m − 1) = 2415 by trial and

error.

Evaluating m2 + m × (m − 1) when m = 30, we get 302 + 30 × 29 = 1770, and so m is greater

than 30.

When m = 33, we get 332 + 33 × 32 = 2145.

When m = 34, we get 342 + 34 × 33 = 2278.

When m = 35, we get 352 + 35 × 34 = 2415, as required.

Answer: (D)

Step-by-step explanation:

8 0
3 years ago
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