23, 29, 31,
There are 3 prime numbers between 22 and 35
Answer:
The original fraction was ![\frac{4}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B8%7D)
Step-by-step explanation:
<u><em>The correct question is</em></u>
In a certain fraction, the numerator is 4 less than the denominator. If 4 is added to both the numerator and the denominator , the resulting fraction is equal to 8/12. What was the original fraction (not necessarily written in lowest terms)
Let
x ----> the numerator of the original fraction
y ----> the denominator of the original fraction
![\frac{x}{y}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D)
we know that
![x=y-4](https://tex.z-dn.net/?f=x%3Dy-4)
so
the original fraction is
![\frac{y-4}{y}](https://tex.z-dn.net/?f=%5Cfrac%7By-4%7D%7By%7D)
If 4 is added to both the numerator and the denominator , the resulting fraction is equal to 8/12
so
![\frac{y-4+4}{y+4}=\frac{8}{12}](https://tex.z-dn.net/?f=%5Cfrac%7By-4%2B4%7D%7By%2B4%7D%3D%5Cfrac%7B8%7D%7B12%7D)
![\frac{y}{y+4}=\frac{8}{12}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7By%2B4%7D%3D%5Cfrac%7B8%7D%7B12%7D)
Solve for y
![12y=8y+32\\12y-8y=32\\4y=32\\y=8](https://tex.z-dn.net/?f=12y%3D8y%2B32%5C%5C12y-8y%3D32%5C%5C4y%3D32%5C%5Cy%3D8)
<em>Find the value of x</em>
![x=y-4](https://tex.z-dn.net/?f=x%3Dy-4)
![x=8-4=4](https://tex.z-dn.net/?f=x%3D8-4%3D4)
therefore
The original fraction was
![\frac{4}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B8%7D)