Pls pls pls pls pls pls pls pls pls help pls

Can you explain it if you could I don’t get it

Vladimir [108]

Step-by-step explanation:

The Triangle Sum Theorem states that the interior angles of a triangle add up to 180 degrees. A square for an angle symbolizes that the angle is 90 °, as is the case with angle ∠ACB.

Therefore, as ∠CAB = 2x and ∠ABC = 3x, and angles ∠ACB, ∠CAB, and ∠ABC make up the interior angles of the triangle, we can say that ∠ACB + ∠CAB + ∠ABC = 180, so 90 + 2x + 3x = 180

90 + 2x + 3x = 180

90 + 5x = 180

subtract 90 from both sides to separate the x and its coefficient

5x = 90

divide both sides by 5 to separate the x

x = 18

(a) ∠CAB = 2x = 18(2) = 36

(b) ∠ABC = 3x = 18(3) = 54

(c) Any triangle with a 90° angle is called a right triangle. This has a 90° triangle, and is therefore a right triangle. Similarly, a 90° angle in a triangle is called a right angle.

8 0

3 years ago

c)Given a TG, called TG1, that accepts the language L1 and a TG, called TG2, that accepts the language L2, show how to build a n

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

Attachment below

6 0

3 years ago

PLEASE HELP!!! very confused

Leni [432]

Answer:

Step-by-step explanation:

The vertices lie on the x-axis, as is determined by their coordinates. This makes the center of this hyperbola (0, 0) because the center is directly between the vertices. The fact that the foci also lie on the x-axis tells us that this is the main axis. What this also tells us is which way the hyperbola "opens". This one opens to the left and the right as opposed to up and down. The standard form for this hyperbola is:

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$ and so far we have that h = 0 and k = 0.

By definition, a is the distance between the center and the vertices. So a = 5, and a-squared is 25. So we're getting there. Now here's the tricky part.

The expressions for the foci are (h-c, k) and (h+c, k). Since we know the foci lie at +/-13, we can use that to solve for c:

If h+c = 13 and h = 0, then

0 + c = 13 and c = 13.

We need that c value to help us find b:

$c^2=a^2+b^2$ and

$13^2=5^2+b^2$ and

$169=25+b^2$ and

$144=b^2$ so

b = 12. Now we're ready to fill in the equation:

$\frac{x^2}{25}-\frac{y^2}{144}=1$ and there you go!

3 0

3 years ago

Please help

lys-0071 [83]

Part 1
1) The positive integers -----------> D.) The natural numbers
2.) An ordering of quantities -----------> B.) A sequence
3.) 2, 4, 8, 16, . . ., 256 -----------> A.) An example of a finite sequence
4.) 1, 3, 5, 7, . . . -----------> E.) An example of an infinite sequence
5.) No first term is available -----------> C.) The reason the numbers . . . -4, -2, 0, 2, 4, . . . are not a sequence
Part 2
$a_n=n^2+2\\ a_1=1+2=3\\ a_2=4+2=6\\ a_3=9+2=11\\ a_4=16+2=18\\ a_5=25+2=27$
The answers is A.
Part 3
$a_n=-1(\frac{1}{3})^{n-1} \\ a_1=-1(\frac{1}{3})^{1-1}=-1\\ a_2=-1(\frac{1}{3})^{2-1}=-\frac{1}{3}\\ a_3=-1(\frac{1}{3})^{3-1}=--\frac{1}{9}\\ a_4=-1(\frac{1}{3})^{4-1}=--\frac{1}{27}\\ a_5=-1(\frac{1}{3})^{5-1}=--\frac{1}{81}\\$
The answers is B.
Part 4
The pattern in this sequence is:
$a_n=2a^nb^{n-1}$
Let's list first six terms:
$a_n=2a^nb^{n-1}\\
a_1=2a^1b^0=2a\\
a_2=2a^2b^1=2a^2b\\
a_3=2a^3b^2\\
a_4=2a^4b^3\\
a_5=2a^5b^4\\
a_6=2a^6b^5\\$
This is a infinite sequence. The patern is obvious and we could find any term within the sequence.

5 0

3 years ago

The volume of the cylinder below is 108π cm^3.

tresset_1 [31]

Answer:

i think it is d or c idk

Step-by-step explanation

108 divided by 3 is 36 idk if you have to divide by 2 but i think its d

6 0

4 years ago