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DerKrebs [107]
3 years ago
11

Tessa buy candy that cost $4 per pound. she will spend more than $40 on candy. what are the possible number of pounds she will b

uy?​
Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

She will buy at least 10 pounds or more.

Step-by-step explanation:

If each pound costs $4 and she is spending $40 worth, she needs to buy 10 pounds in order to spend the minimum of $40. She can buy more than 10 pounds to keep spending more money. 11, 12, 13, 14, 15, and so forth are all possible numbers in pounds she will buy.

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The coordinates of the endpoints of directed line sergeant ABC are A(-8,7) and C(7,-13). If AB:BC = 3:2 then the coordinates of
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The correct answer is A) (1,-5)

Further explanation:

Given points are:

A(-8,7)=(x1,y1)

C(7,13)=(x2,y2)

IT is also given that

AB:BC=3:2

Which means that B divides the line segment in 3:2

Here,

m=3

n=2

To find the coordinates of B

x_B=\frac{mx_2+nx_1}{m+n}\\ = \frac{(3)(7)+(2)(-8)}{3+2}\\=\frac{21-16}{5}\\=\frac{5}{5}\\=1\\y_B=\frac{my_2+ny_1}{m+n}\\=\frac{(3)(-13)+(2)(7)}{3+2}\\=\frac{-39+14}{5}\\=\frac{-25}{5}\\=-5

The coordinates of point B are (1,-5)

The correct answer is A) (1,-5)

Keywords: Coordinate geometry, mid-point

Learn more about coordinate geometry at:

  • brainly.com/question/4819659
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3 years ago
Lesson 9 problem set <br> 5.1
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If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
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Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

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3 years ago
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