Select all equations that represent nonlinear functions.

A teacher tells 6 students the title of the next school play. Those 6 students each tell the title to 6 students. Then those add

Sergio [31]

18 students have been told the title of the next play because 6+6+6=18

3 0

2 years ago

Shawna climbed 5 flights of stairs. There were 9 steps in each flight. How many steps did Shawna climb?

exis [7]

Shawna will climb 45 steps

The first step is to write out the parameters given in the question

Shawna climbed 5 flights of stairs

There were 9 steps in each flight

The number of steps can be calculated by multiplying the number of flight of stairs by the number of steps

= 9 × 5

= 45

Hence there are 45 steps for Shawna to climb

#SPJ1

5 0

2 years ago

At Costco, you can buy a ten-pound bag of Halloween candy for $23.99. Kroger is running a special on the same brand of candy: bu

kirill [66]

Answer:

A. 2.40

B. 4

C. Costco is the better deal

Step-by-step explanation:

23.99/10= 2.399 (rounded to 2.40)

10/2.5 lbs (16 oz = 1 lb) = 4

6 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

2.

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

2 years ago

The rectangle shown has a perimeter of 106 cm and the given area. It’s length is 8 more than four times the width. Write and sol

jeka94

Answer:

Step-by-step explanation:

p = 106

L = 8 + 4W

p = 2L + 2W

p = 2(8 + 4W) + 2W

p = 16 + 8W + 2 W

p = 16 + 10W

106 = 16 + 10W

106 - 16 = 10W

90 = 10W

90/10 = W

9 = W

L = 8 + 4W

L = 8 + 4(9)

L = 8 + 36

44 + 44 + 9 + 9 = 106

44 * 9 = Area = 396

6 0

2 years ago