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kolbaska11 [484]
3 years ago
8

About 9% of the population has a particular genetic mutation. 900 people are randomly selected. Find the standard deviation for

the number of people with the genetic mutation in such groups of 900.
Mathematics
1 answer:
timama [110]3 years ago
3 0

Answer:

The standard deviation is of 8.586.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a genetic mutation, or they do not. The probability of a person having the mutation is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

About 9% of the population has a particular genetic mutation.

This means that p = 0.09

900 people are randomly selected.

This means that n = 900

Find the standard deviation for the number of people with the genetic mutation in such groups of 900.

\sqrt{V(X)} = \sqrt{900*0.09*0.91} = 8.586

The standard deviation is of 8.586.

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